Line slope calculator 2x-8y=-62
Straight line given by points A[1; 8] and B[9; 10]
Calculation:
Slope: m = 0.25Slope-intercept form of line: y = 0.25x+7.75
Canonical form of the line equation: 2x-8y+62 = 0
Parametric form of the line equation:
x = 8t+1
y = 2t+8 ; t ∈ R
Slope angle of line: φ = 14°2'10″ = 0.245 rad
X intercept: x0 = -31
Y intercept: y0 = q = 7.75
Distance line from the origin: d0 = 7.5186
The length of the segment AB: |AB| = 8.2462
Vector: AB = (8; 2)
Normal vector: n = (2; -8)
Midpoint of the segment AB: M = [5; 9]
Perpendicular Bisector equation: 8x+2y-58 = 0
Vector OA = (1; 8) ; |OA| = 8.0623
Vector OB = (9; 10) ; |OB| = 13.4536
Scalar product OA .OB = 89
Angle ∠ AOB = 34°51'44″ = 0.6085 rad