Line slope calculator 8x-3y=16
Straight line given by points A[2; 0] and B[5; 8]
Calculation:
Slope: m = 2.6667Slope-intercept form of line: y = 2.6667x-5.3333
Canonical form of the line equation: 8x-3y-16 = 0
Parametric form of the line equation:
x = 3t+2
y = 8t ; t ∈ R
Slope angle of line: φ = 69°26'38″ = 1.212 rad
X intercept: x0 = 2
Y intercept: y0 = q = -5.3333
Distance line from the origin: d0 = 1.8727
The length of the segment AB: |AB| = 8.544
Vector: AB = (3; 8)
Normal vector: n = (8; -3)
Midpoint of the segment AB: M = [3.5; 4]
Perpendicular Bisector equation: 3x+8y-42.5 = 0
Vector OA = (2; 0) ; |OA| = 2
Vector OB = (5; 8) ; |OB| = 9.434
Scalar product OA .OB = 10
Angle ∠ AOB = 57°59'41″ = 1.0122 rad