Line slope calculator 6x+10y=100
Straight line given by points A[0; 10] and B[10; 4]
Calculation:
Slope: m = -0.6Slope-intercept form of line: y = -0.6x+10
Canonical form of the line equation: 6x+10y-100 = 0
Parametric form of the line equation:
x = 10t
y = -6t+10 ; t ∈ R
Slope angle of line: φ = -30°57'50″ = -0.5404 rad
X intercept: x0 = 16.6667
Y intercept: y0 = q = 10
Distance line from the origin: d0 = 8.5749
The length of the segment AB: |AB| = 11.6619
Vector: AB = (10; -6)
Normal vector: n = (6; 10)
Midpoint of the segment AB: M = [5; 7]
Perpendicular Bisector equation: 10x-6y-8 = 0
Vector OA = (0; 10) ; |OA| = 10
Vector OB = (10; 4) ; |OB| = 10.7703
Scalar product OA .OB = 40
Angle ∠ AOB = 68°11'55″ = 1.1903 rad