Line slope calculator 3x+4y=12
Straight line given by points A[0; 3] and B[4; 0]
Calculation:
Slope: m = -0.75Slope-intercept form of line: y = -0.75x+3
Canonical form of the line equation: 3x+4y-12 = 0
Parametric form of the line equation:
x = 4t
y = -3t+3 ; t ∈ R
Slope angle of line: φ = -36°52'12″ = -0.6435 rad
X intercept: x0 = 4
Y intercept: y0 = q = 3
Distance line from the origin: d0 = 2.4
The length of the segment AB: |AB| = 5
Vector: AB = (4; -3)
Normal vector: n = (3; 4)
Midpoint of the segment AB: M = [2; 1.5]
Perpendicular Bisector equation: 4x-3y-3.5 = 0
Vector OA = (0; 3) ; |OA| = 3
Vector OB = (4; 0) ; |OB| = 4
Scalar product OA .OB = 0
Angle ∠ AOB = 90° = 1.5708 rad