Line slope calculator 3x+5y=15
Straight line given by points A[0; 3] and B[5; 0]
Calculation:
Slope: m = -0.6Slope-intercept form of line: y = -0.6x+3
Canonical form of the line equation: 3x+5y-15 = 0
Parametric form of the line equation:
x = 5t
y = -3t+3 ; t ∈ R
Slope angle of line: φ = -30°57'50″ = -0.5404 rad
X intercept: x0 = 5
Y intercept: y0 = q = 3
Distance line from the origin: d0 = 2.5725
The length of the segment AB: |AB| = 5.831
Vector: AB = (5; -3)
Normal vector: n = (3; 5)
Midpoint of the segment AB: M = [2.5; 1.5]
Perpendicular Bisector equation: 5x-3y-8 = 0
Vector OA = (0; 3) ; |OA| = 3
Vector OB = (5; 0) ; |OB| = 5
Scalar product OA .OB = 0
Angle ∠ AOB = 90° = 1.5708 rad