Line slope calculator 3x-5y=-15
Straight line given by points A[0; 3] and B[5; 6]
Calculation:
Slope: m = 0.6Slope-intercept form of line: y = 0.6x+3
Canonical form of the line equation: 3x-5y+15 = 0
Parametric form of the line equation:
x = 5t
y = 3t+3 ; t ∈ R
Slope angle of line: φ = 30°57'50″ = 0.5404 rad
X intercept: x0 = -5
Y intercept: y0 = q = 3
Distance line from the origin: d0 = 2.5725
The length of the segment AB: |AB| = 5.831
Vector: AB = (5; 3)
Normal vector: n = (3; -5)
Midpoint of the segment AB: M = [2.5; 4.5]
Perpendicular Bisector equation: 5x+3y-26 = 0
Vector OA = (0; 3) ; |OA| = 3
Vector OB = (5; 6) ; |OB| = 7.8102
Scalar product OA .OB = 18
Angle ∠ AOB = 39°48'20″ = 0.6947 rad