Line slope calculator 3x+2y=10
Straight line given by points A[0; 5] and B[2; 2]
Calculation:
Slope: m = -1.5Slope-intercept form of line: y = -1.5x+5
Canonical form of the line equation: 3x+2y-10 = 0
Parametric form of the line equation:
x = 2t
y = -3t+5 ; t ∈ R
Slope angle of line: φ = -56°18'36″ = -0.9828 rad
X intercept: x0 = 3.3333
Y intercept: y0 = q = 5
Distance line from the origin: d0 = 2.7735
The length of the segment AB: |AB| = 3.6056
Vector: AB = (2; -3)
Normal vector: n = (3; 2)
Midpoint of the segment AB: M = [1; 3.5]
Perpendicular Bisector equation: 2x-3y+8.5 = 0
Vector OA = (0; 5) ; |OA| = 5
Vector OB = (2; 2) ; |OB| = 2.8284
Scalar product OA .OB = 10
Angle ∠ AOB = 45° = 0.7854 rad