Line slope calculator 4x+7y=42
Straight line given by points A[0; 6] and B[7; 2]
Calculation:
Slope: m = -0.5714Slope-intercept form of line: y = -0.5714x+6
Canonical form of the line equation: 4x+7y-42 = 0
Parametric form of the line equation:
x = 7t
y = -4t+6 ; t ∈ R
Slope angle of line: φ = -29°44'42″ = -0.5191 rad
X intercept: x0 = 10.5
Y intercept: y0 = q = 6
Distance line from the origin: d0 = 5.2095
The length of the segment AB: |AB| = 8.0623
Vector: AB = (7; -4)
Normal vector: n = (4; 7)
Midpoint of the segment AB: M = [3.5; 4]
Perpendicular Bisector equation: 7x-4y-8.5 = 0
Vector OA = (0; 6) ; |OA| = 6
Vector OB = (7; 2) ; |OB| = 7.2801
Scalar product OA .OB = 12
Angle ∠ AOB = 74°3'17″ = 1.2925 rad