Line slope calculator 2x-5y=-18
Straight line given by points A[1; 4] and B[6; 6]
Calculation:
Slope: m = 0.4Slope-intercept form of line: y = 0.4x+3.6
Canonical form of the line equation: 2x-5y+18 = 0
Parametric form of the line equation:
x = 5t+1
y = 2t+4 ; t ∈ R
Slope angle of line: φ = 21°48'5″ = 0.3805 rad
X intercept: x0 = -9
Y intercept: y0 = q = 3.6
Distance line from the origin: d0 = 3.3425
The length of the segment AB: |AB| = 5.3852
Vector: AB = (5; 2)
Normal vector: n = (2; -5)
Midpoint of the segment AB: M = [3.5; 5]
Perpendicular Bisector equation: 5x+2y-27.5 = 0
Vector OA = (1; 4) ; |OA| = 4.1231
Vector OB = (6; 6) ; |OB| = 8.4853
Scalar product OA .OB = 30
Angle ∠ AOB = 30°57'50″ = 0.5404 rad