Line slope calculator 4x+y=12
Straight line given by points A[1; 8] and B[2; 4]
Calculation:
Slope: m = -4Slope-intercept form of line: y = -4x+12
Canonical form of the line equation: 4x+y-12 = 0
Parametric form of the line equation:
x = t+1
y = -4t+8 ; t ∈ R
Slope angle of line: φ = -75°57'50″ = -1.3258 rad
X intercept: x0 = 3
Y intercept: y0 = q = 12
Distance line from the origin: d0 = 2.9104
The length of the segment AB: |AB| = 4.1231
Vector: AB = (1; -4)
Normal vector: n = (4; 1)
Midpoint of the segment AB: M = [1.5; 6]
Perpendicular Bisector equation: x-4y+22.5 = 0
Vector OA = (1; 8) ; |OA| = 8.0623
Vector OB = (2; 4) ; |OB| = 4.4721
Scalar product OA .OB = 34
Angle ∠ AOB = 19°26'24″ = 0.3393 rad