Line slope calculator 5x-4y=-10
Straight line given by points A[2; 5] and B[6; 10]
Calculation:
Slope: m = 1.25Slope-intercept form of line: y = 1.25x+2.5
Canonical form of the line equation: 5x-4y+10 = 0
Parametric form of the line equation:
x = 4t+2
y = 5t+5 ; t ∈ R
Slope angle of line: φ = 51°20'25″ = 0.8961 rad
X intercept: x0 = -2
Y intercept: y0 = q = 2.5
Distance line from the origin: d0 = 1.5617
The length of the segment AB: |AB| = 6.4031
Vector: AB = (4; 5)
Normal vector: n = (5; -4)
Midpoint of the segment AB: M = [4; 7.5]
Perpendicular Bisector equation: 4x+5y-53.5 = 0
Vector OA = (2; 5) ; |OA| = 5.3852
Vector OB = (6; 10) ; |OB| = 11.6619
Scalar product OA .OB = 62
Angle ∠ AOB = 9°9'44″ = 0.1599 rad