Line slope calculator 10x-7y=30
Straight line given by points A[3; 0] and B[10; 10]
Calculation:
Slope: m = 1.4286Slope-intercept form of line: y = 1.4286x-4.2857
Canonical form of the line equation: 10x-7y-30 = 0
Parametric form of the line equation:
x = 7t+3
y = 10t ; t ∈ R
Slope angle of line: φ = 55°29″ = 0.9601 rad
X intercept: x0 = 3
Y intercept: y0 = q = -4.2857
Distance line from the origin: d0 = 2.4577
The length of the segment AB: |AB| = 12.2066
Vector: AB = (7; 10)
Normal vector: n = (10; -7)
Midpoint of the segment AB: M = [6.5; 5]
Perpendicular Bisector equation: 7x+10y-95.5 = 0
Vector OA = (3; 0) ; |OA| = 3
Vector OB = (10; 10) ; |OB| = 14.1421
Scalar product OA .OB = 30
Angle ∠ AOB = 45° = 0.7854 rad