Line slope calculator 7x+5y=71
Straight line given by points A[3; 10] and B[8; 3]
Calculation:
Slope: m = -1.4Slope-intercept form of line: y = -1.4x+14.2
Canonical form of the line equation: 7x+5y-71 = 0
Parametric form of the line equation:
x = 5t+3
y = -7t+10 ; t ∈ R
Slope angle of line: φ = -54°27'44″ = -0.9505 rad
X intercept: x0 = 10.1429
Y intercept: y0 = q = 14.2
Distance line from the origin: d0 = 8.2536
The length of the segment AB: |AB| = 8.6023
Vector: AB = (5; -7)
Normal vector: n = (7; 5)
Midpoint of the segment AB: M = [5.5; 6.5]
Perpendicular Bisector equation: 5x-7y+18 = 0
Vector OA = (3; 10) ; |OA| = 10.4403
Vector OB = (8; 3) ; |OB| = 8.544
Scalar product OA .OB = 54
Angle ∠ AOB = 52°44'41″ = 0.9206 rad