Line slope calculator x+5y=13
Straight line given by points A[3; 2] and B[8; 1]
Calculation:
Slope: m = -0.2Slope-intercept form of line: y = -0.2x+2.6
Canonical form of the line equation: x+5y-13 = 0
Parametric form of the line equation:
x = 5t+3
y = -t+2 ; t ∈ R
Slope angle of line: φ = -11°18'36″ = -0.1974 rad
X intercept: x0 = 13
Y intercept: y0 = q = 2.6
Distance line from the origin: d0 = 2.5495
The length of the segment AB: |AB| = 5.099
Vector: AB = (5; -1)
Normal vector: n = (1; 5)
Midpoint of the segment AB: M = [5.5; 1.5]
Perpendicular Bisector equation: 5x-y-26 = 0
Vector OA = (3; 2) ; |OA| = 3.6056
Vector OB = (8; 1) ; |OB| = 8.0623
Scalar product OA .OB = 26
Angle ∠ AOB = 26°33'54″ = 0.4636 rad