Line slope calculator 5x-4y=3
Straight line given by points A[3; 3] and B[7; 8]
Calculation:
Slope: m = 1.25Slope-intercept form of line: y = 1.25x-0.75
Canonical form of the line equation: 5x-4y-3 = 0
Parametric form of the line equation:
x = 4t+3
y = 5t+3 ; t ∈ R
Slope angle of line: φ = 51°20'25″ = 0.8961 rad
X intercept: x0 = 0.6
Y intercept: y0 = q = -0.75
Distance line from the origin: d0 = 0.4685
The length of the segment AB: |AB| = 6.4031
Vector: AB = (4; 5)
Normal vector: n = (5; -4)
Midpoint of the segment AB: M = [5; 5.5]
Perpendicular Bisector equation: 4x+5y-47.5 = 0
Vector OA = (3; 3) ; |OA| = 4.2426
Vector OB = (7; 8) ; |OB| = 10.6301
Scalar product OA .OB = 45
Angle ∠ AOB = 3°48'51″ = 0.0666 rad