Line slope calculator x+5y=23
Straight line given by points A[3; 4] and B[8; 3]
Calculation:
Slope: m = -0.2Slope-intercept form of line: y = -0.2x+4.6
Canonical form of the line equation: x+5y-23 = 0
Parametric form of the line equation:
x = 5t+3
y = -t+4 ; t ∈ R
Slope angle of line: φ = -11°18'36″ = -0.1974 rad
X intercept: x0 = 23
Y intercept: y0 = q = 4.6
Distance line from the origin: d0 = 4.5107
The length of the segment AB: |AB| = 5.099
Vector: AB = (5; -1)
Normal vector: n = (1; 5)
Midpoint of the segment AB: M = [5.5; 3.5]
Perpendicular Bisector equation: 5x-y-24 = 0
Vector OA = (3; 4) ; |OA| = 5
Vector OB = (8; 3) ; |OB| = 8.544
Scalar product OA .OB = 36
Angle ∠ AOB = 32°34'27″ = 0.5685 rad