Line slope calculator 5x+7y=50
Straight line given by points A[3; 5] and B[10; 0]
Calculation:
Slope: m = -0.7143Slope-intercept form of line: y = -0.7143x+7.1429
Canonical form of the line equation: 5x+7y-50 = 0
Parametric form of the line equation:
x = 7t+3
y = -5t+5 ; t ∈ R
Slope angle of line: φ = -35°32'16″ = -0.6202 rad
X intercept: x0 = 10
Y intercept: y0 = q = 7.1429
Distance line from the origin: d0 = 5.8124
The length of the segment AB: |AB| = 8.6023
Vector: AB = (7; -5)
Normal vector: n = (5; 7)
Midpoint of the segment AB: M = [6.5; 2.5]
Perpendicular Bisector equation: 7x-5y-33 = 0
Vector OA = (3; 5) ; |OA| = 5.831
Vector OB = (10; 0) ; |OB| = 10
Scalar product OA .OB = 30
Angle ∠ AOB = 59°2'10″ = 1.0304 rad