Line slope calculator 4x+y=20
Straight line given by points A[3; 8] and B[4; 4]
Calculation:
Slope: m = -4Slope-intercept form of line: y = -4x+20
Canonical form of the line equation: 4x+y-20 = 0
Parametric form of the line equation:
x = t+3
y = -4t+8 ; t ∈ R
Slope angle of line: φ = -75°57'50″ = -1.3258 rad
X intercept: x0 = 5
Y intercept: y0 = q = 20
Distance line from the origin: d0 = 4.8507
The length of the segment AB: |AB| = 4.1231
Vector: AB = (1; -4)
Normal vector: n = (4; 1)
Midpoint of the segment AB: M = [3.5; 6]
Perpendicular Bisector equation: x-4y+20.5 = 0
Vector OA = (3; 8) ; |OA| = 8.544
Vector OB = (4; 4) ; |OB| = 5.6569
Scalar product OA .OB = 44
Angle ∠ AOB = 24°26'38″ = 0.4266 rad