Line slope calculator 3x-5y=12
Straight line given by points A[4; 0] and B[9; 3]
Calculation:
Slope: m = 0.6Slope-intercept form of line: y = 0.6x-2.4
Canonical form of the line equation: 3x-5y-12 = 0
Parametric form of the line equation:
x = 5t+4
y = 3t ; t ∈ R
Slope angle of line: φ = 30°57'50″ = 0.5404 rad
X intercept: x0 = 4
Y intercept: y0 = q = -2.4
Distance line from the origin: d0 = 2.058
The length of the segment AB: |AB| = 5.831
Vector: AB = (5; 3)
Normal vector: n = (3; -5)
Midpoint of the segment AB: M = [6.5; 1.5]
Perpendicular Bisector equation: 5x+3y-37 = 0
Vector OA = (4; 0) ; |OA| = 4
Vector OB = (9; 3) ; |OB| = 9.4868
Scalar product OA .OB = 36
Angle ∠ AOB = 18°26'6″ = 0.3218 rad