Line slope calculator 5x+3y=50
Straight line given by points A[4; 10] and B[7; 5]
Calculation:
Slope: m = -1.6667Slope-intercept form of line: y = -1.6667x+16.6667
Canonical form of the line equation: 5x+3y-50 = 0
Parametric form of the line equation:
x = 3t+4
y = -5t+10 ; t ∈ R
Slope angle of line: φ = -59°2'10″ = -1.0304 rad
X intercept: x0 = 10
Y intercept: y0 = q = 16.6667
Distance line from the origin: d0 = 8.5749
The length of the segment AB: |AB| = 5.831
Vector: AB = (3; -5)
Normal vector: n = (5; 3)
Midpoint of the segment AB: M = [5.5; 7.5]
Perpendicular Bisector equation: 3x-5y+21 = 0
Vector OA = (4; 10) ; |OA| = 10.7703
Vector OB = (7; 5) ; |OB| = 8.6023
Scalar product OA .OB = 78
Angle ∠ AOB = 32°39'39″ = 0.57 rad