Line slope calculator 3x+4y=39
Straight line given by points A[5; 6] and B[9; 3]
Calculation:
Slope: m = -0.75Slope-intercept form of line: y = -0.75x+9.75
Canonical form of the line equation: 3x+4y-39 = 0
Parametric form of the line equation:
x = 4t+5
y = -3t+6 ; t ∈ R
Slope angle of line: φ = -36°52'12″ = -0.6435 rad
X intercept: x0 = 13
Y intercept: y0 = q = 9.75
Distance line from the origin: d0 = 7.8
The length of the segment AB: |AB| = 5
Vector: AB = (4; -3)
Normal vector: n = (3; 4)
Midpoint of the segment AB: M = [7; 4.5]
Perpendicular Bisector equation: 4x-3y-14.5 = 0
Vector OA = (5; 6) ; |OA| = 7.8102
Vector OB = (9; 3) ; |OB| = 9.4868
Scalar product OA .OB = 63
Angle ∠ AOB = 31°45'34″ = 0.5543 rad