Line slope calculator 5x+3y=60
Straight line given by points A[6; 10] and B[9; 5]
Calculation:
Slope: m = -1.6667Slope-intercept form of line: y = -1.6667x+20
Canonical form of the line equation: 5x+3y-60 = 0
Parametric form of the line equation:
x = 3t+6
y = -5t+10 ; t ∈ R
Slope angle of line: φ = -59°2'10″ = -1.0304 rad
X intercept: x0 = 12
Y intercept: y0 = q = 20
Distance line from the origin: d0 = 10.2899
The length of the segment AB: |AB| = 5.831
Vector: AB = (3; -5)
Normal vector: n = (5; 3)
Midpoint of the segment AB: M = [7.5; 7.5]
Perpendicular Bisector equation: 3x-5y+15 = 0
Vector OA = (6; 10) ; |OA| = 11.6619
Vector OB = (9; 5) ; |OB| = 10.2956
Scalar product OA .OB = 104
Angle ∠ AOB = 29°58'54″ = 0.5233 rad