Line slope calculator 3x+4y=50
Straight line given by points A[6; 8] and B[10; 5]
Calculation:
Slope: m = -0.75Slope-intercept form of line: y = -0.75x+12.5
Canonical form of the line equation: 3x+4y-50 = 0
Parametric form of the line equation:
x = 4t+6
y = -3t+8 ; t ∈ R
Slope angle of line: φ = -36°52'12″ = -0.6435 rad
X intercept: x0 = 16.6667
Y intercept: y0 = q = 12.5
Distance line from the origin: d0 = 10
The length of the segment AB: |AB| = 5
Vector: AB = (4; -3)
Normal vector: n = (3; 4)
Midpoint of the segment AB: M = [8; 6.5]
Perpendicular Bisector equation: 4x-3y-12.5 = 0
Vector OA = (6; 8) ; |OA| = 10
Vector OB = (10; 5) ; |OB| = 11.1803
Scalar product OA .OB = 100
Angle ∠ AOB = 26°33'54″ = 0.4636 rad