Line slope calculator 5x+y=38
Straight line given by points A[6; 8] and B[7; 3]
Calculation:
Slope: m = -5Slope-intercept form of line: y = -5x+38
Canonical form of the line equation: 5x+y-38 = 0
Parametric form of the line equation:
x = t+6
y = -5t+8 ; t ∈ R
Slope angle of line: φ = -78°41'24″ = -1.3734 rad
X intercept: x0 = 7.6
Y intercept: y0 = q = 38
Distance line from the origin: d0 = 7.4524
The length of the segment AB: |AB| = 5.099
Vector: AB = (1; -5)
Normal vector: n = (5; 1)
Midpoint of the segment AB: M = [6.5; 5.5]
Perpendicular Bisector equation: x-5y+21 = 0
Vector OA = (6; 8) ; |OA| = 10
Vector OB = (7; 3) ; |OB| = 7.6158
Scalar product OA .OB = 66
Angle ∠ AOB = 29°55'53″ = 0.5224 rad