Line slope calculator 4x-3y=-3


Enter coordinates of two different points:

Straight line given by points A[0; 1] and B[3; 5]

Calculation:

Slope-intercept form of line: y = 1.3333x+1

Canonical form of the line equation: 4x-3y+3 = 0

Parametric form of the line equation:
x = 3t
y = 4t+1      ; t ∈ R

Slope: m = 1.3333

Slope angle of line: φ = 53°7'48″ = 0.9273 rad

X intercept: x0 = -0.75

Y intercept: y0 = q = 1

Distance line from the origin: d0 = 0.6

The length of the segment AB: |AB| = 5

Vector: AB = (3; 4)

Normal vector: n = (4; -3)

Midpoint of the segment AB: M = [1.5; 3]

Perpendicular Bisector equation: 3x+4y-16.5 = 0


Vector OA = (0; 1) ;   |OA| = 1
Vector OB = (3; 5) ;   |OB| = 5.831
Scalar product OA .OB = 5
Angle ∠ AOB = 30°57'50″ = 0.5404 rad