Line slope calculator 4x-5y=-5
Straight line given by points A[0; 1] and B[5; 5]
Calculation:
Slope: m = 0.8Slope-intercept form of line: y = 0.8x+1
Canonical form of the line equation: 4x-5y+5 = 0
Parametric form of the line equation:
x = 5t
y = 4t+1 ; t ∈ R
Slope angle of line: φ = 38°39'35″ = 0.6747 rad
X intercept: x0 = -1.25
Y intercept: y0 = q = 1
Distance line from the origin: d0 = 0.7809
The length of the segment AB: |AB| = 6.4031
Vector: AB = (5; 4)
Normal vector: n = (4; -5)
Midpoint of the segment AB: M = [2.5; 3]
Perpendicular Bisector equation: 5x+4y-24.5 = 0
Vector OA = (0; 1) ; |OA| = 1
Vector OB = (5; 5) ; |OB| = 7.0711
Scalar product OA .OB = 5
Angle ∠ AOB = 45° = 0.7854 rad