Line slope calculator 3x-10y=-20


Enter coordinates of two different points:

Straight line given by points A[0; 2] and B[10; 5]

Calculation:

Slope-intercept form of line: y = 0.3x+2

Canonical form of the line equation: 3x-10y+20 = 0

Parametric form of the line equation:
x = 10t
y = 3t+2      ; t ∈ R

Slope: m = 0.3

Slope angle of line: φ = 16°41'57″ = 0.2915 rad

X intercept: x0 = -6.6667

Y intercept: y0 = q = 2

Distance line from the origin: d0 = 1.9157

The length of the segment AB: |AB| = 10.4403

Vector: AB = (10; 3)

Normal vector: n = (3; -10)

Midpoint of the segment AB: M = [5; 3.5]

Perpendicular Bisector equation: 10x+3y-60.5 = 0


Vector OA = (0; 2) ;   |OA| = 2
Vector OB = (10; 5) ;   |OB| = 11.1803
Scalar product OA .OB = 10
Angle ∠ AOB = 63°26'6″ = 1.1071 rad