Line slope calculator x+4y=12


Enter coordinates of two different points:

Straight line given by points A[0; 3] and B[4; 2]

Calculation:

Slope-intercept form of line: y = -0.25x+3

Canonical form of the line equation: x+4y-12 = 0

Parametric form of the line equation:
x = 4t
y = -t+3      ; t ∈ R

Slope: m = -0.25

Slope angle of line: φ = -14°2'10″ = -0.245 rad

X intercept: x0 = 12

Y intercept: y0 = q = 3

Distance line from the origin: d0 = 2.9104

The length of the segment AB: |AB| = 4.1231

Vector: AB = (4; -1)

Normal vector: n = (1; 4)

Midpoint of the segment AB: M = [2; 2.5]

Perpendicular Bisector equation: 4x-y-5.5 = 0


Vector OA = (0; 3) ;   |OA| = 3
Vector OB = (4; 2) ;   |OB| = 4.4721
Scalar product OA .OB = 6
Angle ∠ AOB = 63°26'6″ = 1.1071 rad