Line slope calculator 7x-5y=-15


Enter coordinates of two different points:

Straight line given by points A[0; 3] and B[5; 10]

Calculation:

Slope-intercept form of line: y = 1.4x+3

Canonical form of the line equation: 7x-5y+15 = 0

Parametric form of the line equation:
x = 5t
y = 7t+3      ; t ∈ R

Slope: m = 1.4

Slope angle of line: φ = 54°27'44″ = 0.9505 rad

X intercept: x0 = -2.1429

Y intercept: y0 = q = 3

Distance line from the origin: d0 = 1.7437

The length of the segment AB: |AB| = 8.6023

Vector: AB = (5; 7)

Normal vector: n = (7; -5)

Midpoint of the segment AB: M = [2.5; 6.5]

Perpendicular Bisector equation: 5x+7y-58 = 0


Vector OA = (0; 3) ;   |OA| = 3
Vector OB = (5; 10) ;   |OB| = 11.1803
Scalar product OA .OB = 30
Angle ∠ AOB = 26°33'54″ = 0.4636 rad