Line slope calculator x+3y=12
Straight line given by points A[0; 4] and B[3; 3]
Calculation:
Slope: m = -0.3333Slope-intercept form of line: y = -0.3333x+4
Canonical form of the line equation: x+3y-12 = 0
Parametric form of the line equation:
x = 3t
y = -t+4 ; t ∈ R
Slope angle of line: φ = -18°26'6″ = -0.3218 rad
X intercept: x0 = 12
Y intercept: y0 = q = 4
Distance line from the origin: d0 = 3.7947
The length of the segment AB: |AB| = 3.1623
Vector: AB = (3; -1)
Normal vector: n = (1; 3)
Midpoint of the segment AB: M = [1.5; 3.5]
Perpendicular Bisector equation: 3x-y-1 = 0
Vector OA = (0; 4) ; |OA| = 4
Vector OB = (3; 3) ; |OB| = 4.2426
Scalar product OA .OB = 12
Angle ∠ AOB = 45° = 0.7854 rad