Line slope calculator 5x+3y=18
Straight line given by points A[0; 6] and B[3; 1]
Calculation:
Slope: m = -1.6667Slope-intercept form of line: y = -1.6667x+6
Canonical form of the line equation: 5x+3y-18 = 0
Parametric form of the line equation:
x = 3t
y = -5t+6 ; t ∈ R
Slope angle of line: φ = -59°2'10″ = -1.0304 rad
X intercept: x0 = 3.6
Y intercept: y0 = q = 6
Distance line from the origin: d0 = 3.087
The length of the segment AB: |AB| = 5.831
Vector: AB = (3; -5)
Normal vector: n = (5; 3)
Midpoint of the segment AB: M = [1.5; 3.5]
Perpendicular Bisector equation: 3x-5y+13 = 0
Vector OA = (0; 6) ; |OA| = 6
Vector OB = (3; 1) ; |OB| = 3.1623
Scalar product OA .OB = 6
Angle ∠ AOB = 71°33'54″ = 1.249 rad