Line slope calculator 3x+7y=42


Enter coordinates of two different points:

Straight line given by points A[0; 6] and B[7; 3]

Calculation:

Slope-intercept form of line: y = -0.4286x+6

Canonical form of the line equation: 3x+7y-42 = 0

Parametric form of the line equation:
x = 7t
y = -3t+6      ; t ∈ R

Slope: m = -0.4286

Slope angle of line: φ = -23°11'55″ = -0.4049 rad

X intercept: x0 = 14

Y intercept: y0 = q = 6

Distance line from the origin: d0 = 5.5149

The length of the segment AB: |AB| = 7.6158

Vector: AB = (7; -3)

Normal vector: n = (3; 7)

Midpoint of the segment AB: M = [3.5; 4.5]

Perpendicular Bisector equation: 7x-3y-11 = 0


Vector OA = (0; 6) ;   |OA| = 6
Vector OB = (7; 3) ;   |OB| = 7.6158
Scalar product OA .OB = 18
Angle ∠ AOB = 66°48'5″ = 1.1659 rad