Line slope calculator 7x+y=8
Straight line given by points A[0; 8] and B[1; 1]
Calculation:
Slope: m = -7Slope-intercept form of line: y = -7x+8
Canonical form of the line equation: 7x+y-8 = 0
Parametric form of the line equation:
x = t
y = -7t+8 ; t ∈ R
Slope angle of line: φ = -81°52'12″ = -1.4289 rad
X intercept: x0 = 1.1429
Y intercept: y0 = q = 8
Distance line from the origin: d0 = 1.1314
The length of the segment AB: |AB| = 7.0711
Vector: AB = (1; -7)
Normal vector: n = (7; 1)
Midpoint of the segment AB: M = [0.5; 4.5]
Perpendicular Bisector equation: x-7y+31 = 0
Vector OA = (0; 8) ; |OA| = 8
Vector OB = (1; 1) ; |OB| = 1.4142
Scalar product OA .OB = 8
Angle ∠ AOB = 45° = 0.7854 rad