Line slope calculator 7x+y=8


Enter coordinates of two different points:

Straight line given by points A[0; 8] and B[1; 1]

Calculation:

Slope-intercept form of line: y = -7x+8

Canonical form of the line equation: 7x+y-8 = 0

Parametric form of the line equation:
x = t
y = -7t+8      ; t ∈ R

Slope: m = -7

Slope angle of line: φ = -81°52'12″ = -1.4289 rad

X intercept: x0 = 1.1429

Y intercept: y0 = q = 8

Distance line from the origin: d0 = 1.1314

The length of the segment AB: |AB| = 7.0711

Vector: AB = (1; -7)

Normal vector: n = (7; 1)

Midpoint of the segment AB: M = [0.5; 4.5]

Perpendicular Bisector equation: x-7y+31 = 0


Vector OA = (0; 8) ;   |OA| = 8
Vector OB = (1; 1) ;   |OB| = 1.4142
Scalar product OA .OB = 8
Angle ∠ AOB = 45° = 0.7854 rad