Line slope calculator 5x+y=8
Straight line given by points A[0; 8] and B[1; 3]
Calculation:
Slope: m = -5Slope-intercept form of line: y = -5x+8
Canonical form of the line equation: 5x+y-8 = 0
Parametric form of the line equation:
x = t
y = -5t+8 ; t ∈ R
Slope angle of line: φ = -78°41'24″ = -1.3734 rad
X intercept: x0 = 1.6
Y intercept: y0 = q = 8
Distance line from the origin: d0 = 1.5689
The length of the segment AB: |AB| = 5.099
Vector: AB = (1; -5)
Normal vector: n = (5; 1)
Midpoint of the segment AB: M = [0.5; 5.5]
Perpendicular Bisector equation: x-5y+27 = 0
Vector OA = (0; 8) ; |OA| = 8
Vector OB = (1; 3) ; |OB| = 3.1623
Scalar product OA .OB = 24
Angle ∠ AOB = 18°26'6″ = 0.3218 rad