Line slope calculator x-3y=-2
Straight line given by points A[1; 1] and B[4; 2]
Calculation:
Slope: m = 0.3333Slope-intercept form of line: y = 0.3333x+0.6667
Canonical form of the line equation: x-3y+2 = 0
Parametric form of the line equation:
x = 3t+1
y = t+1 ; t ∈ R
Slope angle of line: φ = 18°26'6″ = 0.3218 rad
X intercept: x0 = -2
Y intercept: y0 = q = 0.6667
Distance line from the origin: d0 = 0.6325
The length of the segment AB: |AB| = 3.1623
Vector: AB = (3; 1)
Normal vector: n = (1; -3)
Midpoint of the segment AB: M = [2.5; 1.5]
Perpendicular Bisector equation: 3x+y-9 = 0
Vector OA = (1; 1) ; |OA| = 1.4142
Vector OB = (4; 2) ; |OB| = 4.4721
Scalar product OA .OB = 6
Angle ∠ AOB = 18°26'6″ = 0.3218 rad