Line slope calculator 5x+3y=35


Enter coordinates of two different points:

Straight line given by points A[1; 10] and B[4; 5]

Calculation:

Slope-intercept form of line: y = -1.6667x+11.6667

Canonical form of the line equation: 5x+3y-35 = 0

Parametric form of the line equation:
x = 3t+1
y = -5t+10      ; t ∈ R

Slope: m = -1.6667

Slope angle of line: φ = -59°2'10″ = -1.0304 rad

X intercept: x0 = 7

Y intercept: y0 = q = 11.6667

Distance line from the origin: d0 = 6.0025

The length of the segment AB: |AB| = 5.831

Vector: AB = (3; -5)

Normal vector: n = (5; 3)

Midpoint of the segment AB: M = [2.5; 7.5]

Perpendicular Bisector equation: 3x-5y+30 = 0


Vector OA = (1; 10) ;   |OA| = 10.0499
Vector OB = (4; 5) ;   |OB| = 6.4031
Scalar product OA .OB = 54
Angle ∠ AOB = 32°56'57″ = 0.5751 rad