Line slope calculator 5x+3y=35
Straight line given by points A[1; 10] and B[4; 5]
Calculation:
Slope: m = -1.6667Slope-intercept form of line: y = -1.6667x+11.6667
Canonical form of the line equation: 5x+3y-35 = 0
Parametric form of the line equation:
x = 3t+1
y = -5t+10 ; t ∈ R
Slope angle of line: φ = -59°2'10″ = -1.0304 rad
X intercept: x0 = 7
Y intercept: y0 = q = 11.6667
Distance line from the origin: d0 = 6.0025
The length of the segment AB: |AB| = 5.831
Vector: AB = (3; -5)
Normal vector: n = (5; 3)
Midpoint of the segment AB: M = [2.5; 7.5]
Perpendicular Bisector equation: 3x-5y+30 = 0
Vector OA = (1; 10) ; |OA| = 10.0499
Vector OB = (4; 5) ; |OB| = 6.4031
Scalar product OA .OB = 54
Angle ∠ AOB = 32°56'57″ = 0.5751 rad