Line slope calculator 8x-3y=16


Enter coordinates of two different points:

Straight line given by points A[2; 0] and B[5; 8]

Calculation:

Slope-intercept form of line: y = 2.6667x-5.3333

Canonical form of the line equation: 8x-3y-16 = 0

Parametric form of the line equation:
x = 3t+2
y = 8t      ; t ∈ R

Slope: m = 2.6667

Slope angle of line: φ = 69°26'38″ = 1.212 rad

X intercept: x0 = 2

Y intercept: y0 = q = -5.3333

Distance line from the origin: d0 = 1.8727

The length of the segment AB: |AB| = 8.544

Vector: AB = (3; 8)

Normal vector: n = (8; -3)

Midpoint of the segment AB: M = [3.5; 4]

Perpendicular Bisector equation: 3x+8y-42.5 = 0


Vector OA = (2; 0) ;   |OA| = 2
Vector OB = (5; 8) ;   |OB| = 9.434
Scalar product OA .OB = 10
Angle ∠ AOB = 57°59'41″ = 1.0122 rad