Line slope calculator 5x-3y=1
Straight line given by points A[2; 3] and B[5; 8]
Calculation:
Slope: m = 1.6667Slope-intercept form of line: y = 1.6667x-0.3333
Canonical form of the line equation: 5x-3y-1 = 0
Parametric form of the line equation:
x = 3t+2
y = 5t+3 ; t ∈ R
Slope angle of line: φ = 59°2'10″ = 1.0304 rad
X intercept: x0 = 0.2
Y intercept: y0 = q = -0.3333
Distance line from the origin: d0 = 0.1715
The length of the segment AB: |AB| = 5.831
Vector: AB = (3; 5)
Normal vector: n = (5; -3)
Midpoint of the segment AB: M = [3.5; 5.5]
Perpendicular Bisector equation: 3x+5y-38 = 0
Vector OA = (2; 3) ; |OA| = 3.6056
Vector OB = (5; 8) ; |OB| = 9.434
Scalar product OA .OB = 34
Angle ∠ AOB = 1°41'5″ = 0.0294 rad