Line slope calculator 3x+5y=21


Enter coordinates of two different points:

Straight line given by points A[2; 3] and B[7; 0]

Calculation:

Slope-intercept form of line: y = -0.6x+4.2

Canonical form of the line equation: 3x+5y-21 = 0

Parametric form of the line equation:
x = 5t+2
y = -3t+3      ; t ∈ R

Slope: m = -0.6

Slope angle of line: φ = -30°57'50″ = -0.5404 rad

X intercept: x0 = 7

Y intercept: y0 = q = 4.2

Distance line from the origin: d0 = 3.6015

The length of the segment AB: |AB| = 5.831

Vector: AB = (5; -3)

Normal vector: n = (3; 5)

Midpoint of the segment AB: M = [4.5; 1.5]

Perpendicular Bisector equation: 5x-3y-18 = 0


Vector OA = (2; 3) ;   |OA| = 3.6056
Vector OB = (7; 0) ;   |OB| = 7
Scalar product OA .OB = 14
Angle ∠ AOB = 56°18'36″ = 0.9828 rad