Line slope calculator x+5y=17
Straight line given by points A[2; 3] and B[7; 2]
Calculation:
Slope: m = -0.2Slope-intercept form of line: y = -0.2x+3.4
Canonical form of the line equation: x+5y-17 = 0
Parametric form of the line equation:
x = 5t+2
y = -t+3 ; t ∈ R
Slope angle of line: φ = -11°18'36″ = -0.1974 rad
X intercept: x0 = 17
Y intercept: y0 = q = 3.4
Distance line from the origin: d0 = 3.334
The length of the segment AB: |AB| = 5.099
Vector: AB = (5; -1)
Normal vector: n = (1; 5)
Midpoint of the segment AB: M = [4.5; 2.5]
Perpendicular Bisector equation: 5x-y-20 = 0
Vector OA = (2; 3) ; |OA| = 3.6056
Vector OB = (7; 2) ; |OB| = 7.2801
Scalar product OA .OB = 20
Angle ∠ AOB = 40°21'52″ = 0.7045 rad