Line slope calculator x-4y=-1
Straight line given by points A[3; 1] and B[7; 2]
Calculation:
Slope: m = 0.25Slope-intercept form of line: y = 0.25x+0.25
Canonical form of the line equation: x-4y+1 = 0
Parametric form of the line equation:
x = 4t+3
y = t+1 ; t ∈ R
Slope angle of line: φ = 14°2'10″ = 0.245 rad
X intercept: x0 = -1
Y intercept: y0 = q = 0.25
Distance line from the origin: d0 = 0.2425
The length of the segment AB: |AB| = 4.1231
Vector: AB = (4; 1)
Normal vector: n = (1; -4)
Midpoint of the segment AB: M = [5; 1.5]
Perpendicular Bisector equation: 4x+y-21.5 = 0
Vector OA = (3; 1) ; |OA| = 3.1623
Vector OB = (7; 2) ; |OB| = 7.2801
Scalar product OA .OB = 23
Angle ∠ AOB = 2°29'22″ = 0.0435 rad