Line slope calculator 7x+3y=51
Straight line given by points A[3; 10] and B[6; 3]
Calculation:
Slope: m = -2.3333Slope-intercept form of line: y = -2.3333x+17
Canonical form of the line equation: 7x+3y-51 = 0
Parametric form of the line equation:
x = 3t+3
y = -7t+10 ; t ∈ R
Slope angle of line: φ = -66°48'5″ = -1.1659 rad
X intercept: x0 = 7.2857
Y intercept: y0 = q = 17
Distance line from the origin: d0 = 6.6966
The length of the segment AB: |AB| = 7.6158
Vector: AB = (3; -7)
Normal vector: n = (7; 3)
Midpoint of the segment AB: M = [4.5; 6.5]
Perpendicular Bisector equation: 3x-7y+32 = 0
Vector OA = (3; 10) ; |OA| = 10.4403
Vector OB = (6; 3) ; |OB| = 6.7082
Scalar product OA .OB = 48
Angle ∠ AOB = 46°44'9″ = 0.8157 rad