Line slope calculator 9x+5y=77
Straight line given by points A[3; 10] and B[8; 1]
Calculation:
Slope: m = -1.8Slope-intercept form of line: y = -1.8x+15.4
Canonical form of the line equation: 9x+5y-77 = 0
Parametric form of the line equation:
x = 5t+3
y = -9t+10 ; t ∈ R
Slope angle of line: φ = -60°56'43″ = -1.0637 rad
X intercept: x0 = 8.5556
Y intercept: y0 = q = 15.4
Distance line from the origin: d0 = 7.4789
The length of the segment AB: |AB| = 10.2956
Vector: AB = (5; -9)
Normal vector: n = (9; 5)
Midpoint of the segment AB: M = [5.5; 5.5]
Perpendicular Bisector equation: 5x-9y+22 = 0
Vector OA = (3; 10) ; |OA| = 10.4403
Vector OB = (8; 1) ; |OB| = 8.0623
Scalar product OA .OB = 34
Angle ∠ AOB = 66°10'33″ = 1.155 rad