Line slope calculator 3x+4y=29


Enter coordinates of two different points:

Straight line given by points A[3; 5] and B[7; 2]

Calculation:

Slope-intercept form of line: y = -0.75x+7.25

Canonical form of the line equation: 3x+4y-29 = 0

Parametric form of the line equation:
x = 4t+3
y = -3t+5      ; t ∈ R

Slope: m = -0.75

Slope angle of line: φ = -36°52'12″ = -0.6435 rad

X intercept: x0 = 9.6667

Y intercept: y0 = q = 7.25

Distance line from the origin: d0 = 5.8

The length of the segment AB: |AB| = 5

Vector: AB = (4; -3)

Normal vector: n = (3; 4)

Midpoint of the segment AB: M = [5; 3.5]

Perpendicular Bisector equation: 4x-3y-9.5 = 0


Vector OA = (3; 5) ;   |OA| = 5.831
Vector OB = (7; 2) ;   |OB| = 7.2801
Scalar product OA .OB = 31
Angle ∠ AOB = 43°5'27″ = 0.7521 rad