Line slope calculator 7x+3y=45


Enter coordinates of two different points:

Straight line given by points A[3; 8] and B[6; 1]

Calculation:

Slope-intercept form of line: y = -2.3333x+15

Canonical form of the line equation: 7x+3y-45 = 0

Parametric form of the line equation:
x = 3t+3
y = -7t+8      ; t ∈ R

Slope: m = -2.3333

Slope angle of line: φ = -66°48'5″ = -1.1659 rad

X intercept: x0 = 6.4286

Y intercept: y0 = q = 15

Distance line from the origin: d0 = 5.9088

The length of the segment AB: |AB| = 7.6158

Vector: AB = (3; -7)

Normal vector: n = (7; 3)

Midpoint of the segment AB: M = [4.5; 4.5]

Perpendicular Bisector equation: 3x-7y+18 = 0


Vector OA = (3; 8) ;   |OA| = 8.544
Vector OB = (6; 1) ;   |OB| = 6.0828
Scalar product OA .OB = 26
Angle ∠ AOB = 59°58'54″ = 1.0469 rad