Line slope calculator 5x+3y=39


Enter the coordinates of two different points:
Line slope diagram

Straight line given by points A[3; 8] and B[6; 3]

Calculation:

Slope: m = -1.6667

Slope-intercept form of line: y = -1.6667x+13

Canonical form of the line equation: 5x+3y-39 = 0

Parametric form of the line equation:
x = 3t+3
y = -5t+8      ; t ∈ R

Slope angle of line: φ = -59°2'10″ = -1.0304 rad

X intercept: x0 = 7.8

Y intercept: y0 = q = 13

Distance line from the origin: d0 = 6.6884

The length of the segment AB: |AB| = 5.831

Vector: AB = (3; -5)

Normal vector: n = (5; 3)

Midpoint of the segment AB: M = [4.5; 5.5]

Perpendicular Bisector equation: 3x-5y+14 = 0

Vector OA = (3; 8) ;   |OA| = 8.544
Vector OB = (6; 3) ;   |OB| = 6.7082
Scalar product OA .OB = 42
Angle ∠ AOB = 42°52'44″ = 0.7484 rad