Line slope calculator x-5y=-16


Enter coordinates of two different points:

Straight line given by points A[4; 4] and B[9; 5]

Calculation:

Slope-intercept form of line: y = 0.2x+3.2

Canonical form of the line equation: x-5y+16 = 0

Parametric form of the line equation:
x = 5t+4
y = t+4      ; t ∈ R

Slope: m = 0.2

Slope angle of line: φ = 11°18'36″ = 0.1974 rad

X intercept: x0 = -16

Y intercept: y0 = q = 3.2

Distance line from the origin: d0 = 3.1379

The length of the segment AB: |AB| = 5.099

Vector: AB = (5; 1)

Normal vector: n = (1; -5)

Midpoint of the segment AB: M = [6.5; 4.5]

Perpendicular Bisector equation: 5x+y-37 = 0


Vector OA = (4; 4) ;   |OA| = 5.6569
Vector OB = (9; 5) ;   |OB| = 10.2956
Scalar product OA .OB = 56
Angle ∠ AOB = 15°56'43″ = 0.2783 rad