Line slope calculator 5x-4y=25
Straight line given by points A[5; 0] and B[9; 5]
Calculation:
Slope: m = 1.25Slope-intercept form of line: y = 1.25x-6.25
Canonical form of the line equation: 5x-4y-25 = 0
Parametric form of the line equation:
x = 4t+5
y = 5t ; t ∈ R
Slope angle of line: φ = 51°20'25″ = 0.8961 rad
X intercept: x0 = 5
Y intercept: y0 = q = -6.25
Distance line from the origin: d0 = 3.9043
The length of the segment AB: |AB| = 6.4031
Vector: AB = (4; 5)
Normal vector: n = (5; -4)
Midpoint of the segment AB: M = [7; 2.5]
Perpendicular Bisector equation: 4x+5y-40.5 = 0
Vector OA = (5; 0) ; |OA| = 5
Vector OB = (9; 5) ; |OB| = 10.2956
Scalar product OA .OB = 45
Angle ∠ AOB = 29°3'17″ = 0.5071 rad