Line slope calculator x+5y=35
Straight line given by points A[5; 6] and B[10; 5]
Calculation:
Slope: m = -0.2Slope-intercept form of line: y = -0.2x+7
Canonical form of the line equation: x+5y-35 = 0
Parametric form of the line equation:
x = 5t+5
y = -t+6 ; t ∈ R
Slope angle of line: φ = -11°18'36″ = -0.1974 rad
X intercept: x0 = 35
Y intercept: y0 = q = 7
Distance line from the origin: d0 = 6.8641
The length of the segment AB: |AB| = 5.099
Vector: AB = (5; -1)
Normal vector: n = (1; 5)
Midpoint of the segment AB: M = [7.5; 5.5]
Perpendicular Bisector equation: 5x-y-32 = 0
Vector OA = (5; 6) ; |OA| = 7.8102
Vector OB = (10; 5) ; |OB| = 11.1803
Scalar product OA .OB = 80
Angle ∠ AOB = 23°37'46″ = 0.4124 rad