Line slope calculator 2x-3y=12
Straight line given by points A[6; 0] and B[9; 2]
Calculation:
Slope: m = 0.6667Slope-intercept form of line: y = 0.6667x-4
Canonical form of the line equation: 2x-3y-12 = 0
Parametric form of the line equation:
x = 3t+6
y = 2t ; t ∈ R
Slope angle of line: φ = 33°41'24″ = 0.588 rad
X intercept: x0 = 6
Y intercept: y0 = q = -4
Distance line from the origin: d0 = 3.3282
The length of the segment AB: |AB| = 3.6056
Vector: AB = (3; 2)
Normal vector: n = (2; -3)
Midpoint of the segment AB: M = [7.5; 1]
Perpendicular Bisector equation: 3x+2y-24.5 = 0
Vector OA = (6; 0) ; |OA| = 6
Vector OB = (9; 2) ; |OB| = 9.2195
Scalar product OA .OB = 54
Angle ∠ AOB = 12°31'44″ = 0.2187 rad