Line slope calculator 2x-3y=12


Enter coordinates of two different points:

Straight line given by points A[6; 0] and B[9; 2]

Calculation:

Slope-intercept form of line: y = 0.6667x-4

Canonical form of the line equation: 2x-3y-12 = 0

Parametric form of the line equation:
x = 3t+6
y = 2t      ; t ∈ R

Slope: m = 0.6667

Slope angle of line: φ = 33°41'24″ = 0.588 rad

X intercept: x0 = 6

Y intercept: y0 = q = -4

Distance line from the origin: d0 = 3.3282

The length of the segment AB: |AB| = 3.6056

Vector: AB = (3; 2)

Normal vector: n = (2; -3)

Midpoint of the segment AB: M = [7.5; 1]

Perpendicular Bisector equation: 3x+2y-24.5 = 0


Vector OA = (6; 0) ;   |OA| = 6
Vector OB = (9; 2) ;   |OB| = 9.2195
Scalar product OA .OB = 54
Angle ∠ AOB = 12°31'44″ = 0.2187 rad